2x^2-45=4x^2-5

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Solution for 2x^2-45=4x^2-5 equation: 



2x^2-45=4x^2-5

We move all terms to the left:

2x^2-45-(4x^2-5)=0

We get rid of parentheses

2x^2-4x^2+5-45=0

We add all the numbers together, and all the variables

-2x^2-40=0

a = -2; b = 0; c = -40;
Δ = b2-4ac
Δ = 02-4·(-2)·(-40)
Δ = -320
Delta is less than zero, so there is no solution for the equation

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